The dimensions of a cuboidal room are 8.6 metre into 5.4 metre into 4 metre. The room has two doors each measuring 2 metre by 1 metre and 4 windows each measuring 1 by 1 metre.What will be the cost of plastering the four walls and ceiling at rupees 65 per metre square?
Answers
cost of plastering is Rs. 97778.6
Step-by-step explanation:
length of the room = 8.6 m
breadth of the room = 5.4 m
height of the room = 4 m
dimension of door = 2×1
area of 2 doors = 2 × (l×b) = 2× (2) = 4 m ²
area of 4 windows = 4 × (l×b) = 4(1) = 4 m ²
area of 4 walls of the room = 2 (l+b) h
= 2(8.6+ 5.4 ) 4
= 8 (14 )
= 112 m ²
area of celing = l×b = 8.6 ×5.4 = 46.44
area to be plaster = area of 4 walls + area of ceiling-(area of 2 doors + area of 4 windows )
area to be plaster = 112 + 46.44 - (4+4)
= 158.44 - (8)
= 150.44 m ²
cost of plastering 1 m ² = Rs. 65
cost of plastering 150.44 m ² = 150.44 × 65 = Rs. 97778.6
hence , cost of plastering is Rs. 97778.6
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Answer:
*Total Surface Area of cuboid = 2(lb +bh + hl).
Length =8.6m
Breadth = 5.4m
Height = 4m
now, the length of two doors. = 2m
the breadth " " " " "" "" = 1m
So, area of 2 doors are = 2 × l × b.
= 2 × 2 × 1.
= 4m²
*length of four windows = 1m
breadth " " " " = 1m
Area of square = 4 × 4 × side.
= 4 × 4 × 1.
= 16m²
Total area = 4m² +16m²
= 20m²
Now, CSA kf cuboid + area of base rectangle - total area of doors and windows.
=》 2(l + b) + l × b - 20
=》 2(8.6 + 5.4) + 8.6 × 5.4 - 20
=》 2 × 14 + 46.44 - 20.
=》 54.44m^2.
Total cost of plastering= 65.
=》 54.44 × 65
=》 3538.6 rupees.