The dimensions of a metallic cuboid are 100*80*64cm it is melted and recast into cubes
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Volume of the metallic cuboid will be
V=length× breath× height
V= 100 ×80×64
V=512000cubic cm
surface area of the cuboid is 2(length)+2(breath)+2(height)
S=2(100)+2(80)+2(64)
S=488squre cm
So the surface of the cube will be after melting the the cuboid will be
Surface of the cube will be S= 488 square cm
then the length breath and height of the cube will be same that is
L=B=H=488/6=81.33cm
The cube will have all the six faces will be of same dimension so
a= 81.33 cm.
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V=length× breath× height
V= 100 ×80×64
V=512000cubic cm
surface area of the cuboid is 2(length)+2(breath)+2(height)
S=2(100)+2(80)+2(64)
S=488squre cm
So the surface of the cube will be after melting the the cuboid will be
Surface of the cube will be S= 488 square cm
then the length breath and height of the cube will be same that is
L=B=H=488/6=81.33cm
The cube will have all the six faces will be of same dimension so
a= 81.33 cm.
These is the answer for your question
Thank you
Mark me as Brainlist please
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