The dimensions of a rectangular park are 25 m and 16.4 m. Two paths run parallel to the sides of the rectangle through the center of the park. The width of the paths is 1.7m, respectively. Find the area of the paths.
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Answered by
3
let us assume that the paths are PQRS and TUVW
-----------------------------------
Area of rectangle PQRS = l xb
length = 25m
width = 1.7 m
area = 25 x 1.7
=42.5 m²
-------------------------------------------------------------------------------
area of rectangle TUVW = l x b
length =16.4m
readth = 1.7 m
area = 16.4 x 1.7
=27.88 m²
---------------------------------------------------------------------------
total area of paths = area of PQRS + TUVW
=42.5 + 27.88
=70.38 m²
-----------------------------------
Area of rectangle PQRS = l xb
length = 25m
width = 1.7 m
area = 25 x 1.7
=42.5 m²
-------------------------------------------------------------------------------
area of rectangle TUVW = l x b
length =16.4m
readth = 1.7 m
area = 16.4 x 1.7
=27.88 m²
---------------------------------------------------------------------------
total area of paths = area of PQRS + TUVW
=42.5 + 27.88
=70.38 m²
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sudhanshu0010mail:
no its answer is 67.49 sq. metre
Answered by
0
Area= l.b= 25 × 16.4=410
Width of paths 25+1.7= 26.7
16.4+1.7= 18.1
Ther4 26.7 × 18.1= 483.27002
Width of paths 25+1.7= 26.7
16.4+1.7= 18.1
Ther4 26.7 × 18.1= 483.27002
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