Math, asked by sudhanshu0010mail, 1 year ago

The dimensions of a rectangular park are 25 m and 16.4 m. Two paths run parallel to the sides of the rectangle through the center of the park. The width of the paths is 1.7m, respectively. Find the area of the paths.

Answers

Answered by TheRuhanikaDhawan
3
let us assume that the paths are PQRS and TUVW
-----------------------------------
Area of rectangle PQRS = l xb
length = 25m
width  = 1.7 m

area = 25 x 1.7

=42.5 m²
-------------------------------------------------------------------------------
area of rectangle TUVW = l x b
length =16.4m
readth = 1.7 m

area = 16.4 x 1.7 

=27.88 m²
---------------------------------------------------------------------------
total area of paths =  area of PQRS + TUVW

=42.5 + 27.88

=70.38 m²
Attachments:

sudhanshu0010mail: no its answer is 67.49 sq. metre
TheRuhanikaDhawan: 3 units diff na
sudhanshu0010mail: yaa
Answered by hrik21
0
Area= l.b= 25 × 16.4=410

Width of paths 25+1.7= 26.7

16.4+1.7= 18.1
Ther4 26.7 × 18.1= 483.27002
Similar questions