Question

the dimensions of a solid iron cuboid are 4.4 m × 2.6 m × 1.0 m . It is melted and recast into a hollow cylindrical pipe of 40 cm inner radius and thickness 5 cm . Find the length of the pipe .

Answer 1

given,

length=4.4m =4.4×100=440cm

breadth=2.6m=2.6×100=260cm

height=1.0m=100cm

inner radius (r) =40cm

thickness =5cm

outer radius (R) =40+5=45cm

volume of cuboid = volume of pipe

=>lbh=hπ(R²-r²)

=>440×260×100=h 22/7 (45²-40²)

=>20×260×100=h/7 ( 2025-1600)

=>20×260×100=h/7 (425)

=>h=20×260×100×7/425

=>h=8564.7cm=8564.7/100=85.647m

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