Question

The dimensions of alpha ÷ beta in the equation F =( alpha - t^2 )÷ (beta × v^2), where F is the force,v is the velocity and t is time, is

Answer 1

Dimensions of force are  MLT^-2

Considering the equation,

α  -  t²/βv²

So,alpha should also have the same dimension 

α = MLT^-2

Dimension of 

t=T

v= LT^-1

So,

t²/v² = L^-2 T^4

So,

t²/βv²= MLT^-2

So,

β=M^-1  L^-3 T^6

Now,

α/β = M^2 L^4 T^-8

This will be the dimension of α/β