Question

The dimensions of alpha ÷ beta in the equation F = alpha - t2 ÷ beta × v2, where F is the force,v is the velocity and t is time, is

Answer 1

Dimensions of force are  MLT^-2
Considering the equation,
α  -  t²/βv²
So,alpha should also have the same dimension 
α = MLT^-2
Dimension of 
t=T
v= LT^-1
So,
t²/v² = L^-2 T^4

So,
t²/βv²= MLT^-2
So,
β=M^-1  L^-3 T^6
Now,
α/β = M^2 L^4 T^-8

This will be the dimension of α/β

Answer 2

Hope it helps..... The answer should be ML^3T^-4