Physics, asked by snchobi2734, 5 months ago

The dimensions of Planck’s constant are a) [M2L 2T −2 ] b) [MLT −2 ] c) [ML 2T −2 ] d) [ML 2T −1 ]

Answers

Answered by simransaini4988
0

Answer:

ML^2T^-1

Explanation

h=E/v

here

E= energy => dimensional formula=ML2T2

v = frequency => dimensional formula = T-1

h= planks constt.

=>

ML2T2

h= ----------- => ML2T-1

T-1

Answered by harshapilla0000
0

Answer:

d) [M^1 L^2 T^-1]

Explanation:

this is the ans for the above question which u have given.

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