The dimensions of rectangular block of mass 10 kg kept on table are a(10.2 x0.1x0.05) m. Find the pressure exerted by the block, if it is kept on the table with sides of dimensions
() (10.2 x 0.) m' and (ii) (10.1x 0.05) m.
(Take, g = 10 m -4)
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The “standard” acceleration (at sea level and 45° latitude) due to gravity is 9.80665 m/s2. What is the force needed to hold a mass of 2 kg at rest in this gravitational field ? How much mass can a force of 1 N support ? Solution: ma = 0 = ∑ F = F - mg F = mg = 2 × 9.80665 = 19.613 N F = mg 2.2 => m = F/g = 1 / 9.80665 = 0.102 kg A model car rolls down an incline with a slope so the gravitational “pull” in the direction of motion is one third of the standard gravitational force (see Problem
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