Question

The dimensions of root μrg , where μ is the coefficient of friction, r is radius of circular path and g
is the acceleration due to gravity are equivalent to the dimensions of

Answer 1

Answer:

its Equal to the dimensions of velocity

Explanation:

velocity = √ radius x g x friction coefficient

Answer 2

Answer:

The magnetic force  $[v]=\left[\frac{F}{q B}\right] \text {. }$

Explanation:

The acceleration of freely falling bodies due to the force of attraction of the other body exists named Acceleration due to gravity. It exists a constant amount for a given attracting body at a given place.

Magnetic force, attraction, or repulsion that occurs between electrically charged particles because of their action.

$\sqrt{\mu r g}=\sqrt{M^{0} L^{0} T^{0} L\left(L T^{-2}\right)}$

$[\mu r g]=\left[L T^{-1}\right]=[ velocity ] .$

Now, magnetic force, $F=q v B$

$[v]=\left[\frac{F}{q B}\right] \text {. }$

Therefore, the magnetic force

$[v]=\left[\frac{F}{q B}\right] \text {. }$

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