Question

The dimensions of the floor of a rectangular hall are 4m*3m . The floor of the hall is to be tiled fully with 8cm*6cm rectangular tiles without breaking tiles to smaller tiles. Find the number of required tiles

Answer 1

Answer:

l of hall is 4m which is equal to 400cm

b of hall is 3m which is equal to 300cm

Area of hall = l*b= 400*300= 120000cm²

l of tiles is 8cm

b of tiles is 6cm

Area of tiles is 8*6= 48cm²

No. of tiles required

Area of hall / Area of tiles

120000/48= 2500

Hence no. of tiles required is 2500

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Answer 2

Answer :

2500 tiles is required to tile the full floor of the rectangular hall.

Step-by-step explanation :

To Find,

• The number of required tiles

Solution,

Given that,

• The dimensions of the floor of a rectangular hall are 4m × 3m
• The floor of the hall is to be tiled fully with 8cm × 6cm rectangular tiles without breaking tiles to smaller tiles

Converting 4m and 3m, to cm

➭ [ 4 × 100 = 400 cm ] ... ( 1m = 100 cm )

➭ [ 3 × 100 = 300 cm ] ... ( 1m = 100 cm )

As we know that,

Area of rectangle = ( l × b )

Where,

• l = Length
• b = Breadth

Therefore,

Area of the floor of the rectangular hall

➭ 400 cm × 300 cm

➭ 120000 cm²

Area of one tile

➭ 8 cm × 6 cm

➭ 48 cm²

Now, number of tiles required is,

Number of tiles = Area of floor / Area of one tile

Therefore,

➭ 120000 / 48

➭ 2500 ★

Hence, 2500 tiles is required to tile the full rectangular hall.