Question

The dimensions of the quantity hc (where h=h/(2pi)) is

Answer 1

Answer:

[hc] = [h/2π] [c]

= [L/1] [LT^-1]

= [L^2T^-1]

Please don't forget to mark as BRAINLIEST.

Answer 2

Answer:

ML^3T^-2

Explanation:

joule meter

E=hC/lambda

E x lambda = hC

(E x lambda)/2π = hC/2π

J m /1 = hC/2π

[ML^3T^-2]= hC/2π