The dining hall of a hotel is 12.5 m long, 9 m broad and 7 m high. It has two – doors
2.5m by 1.2m each and four windows 1.5 m by 1 m each. Find the cost of papering
its wall at the rate of ₹ 3.50 per m2.
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Explanation:
Given The dining hall of a hotel is 12.5 m long, 9 m broad and 7 m high. It has two doors 2.5m by 1.2m each and four windows 1.5 m by 1 m each. Find the cost of papering its wall at the rate of ₹ 3.50 per m2.
- Given Length of the dining hall of a hotel = 12.5 m
- Breadth of the dining hall of a hotel = 9m
- Height of the dining hall of a hotel = 7m
- Area of four walls of dining hall will be 2 (l + b) x h
- = 2 (12.5 + 9) x 7
- = 2 x 21.5 x 7
- = 301 sq m
- Now Area of one door = 2.5 x 1.2
- = 3 sq m
- Therefore Area of 2 doors will be 3 x 2
- = 6 sq m
- Now Area of one window = 1.5 x 1
- = 1.5 sq m
- Therefore Area of 4 windows will be 1.5 x 4
- = 6 sq m
- Now Area of the walls to be papered will be
- = 301 – (6 + 6)
- = 301 – 12
- = 289 sq m
- So cost of papering the walls at Rs3.50 per m^2
- = 289 x 3.50
- = Rs 1011.5
Reference link will be
https://brainly.in/question/34376822
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