Question

The dipole moment of a diatomic molecule is 4.32 D and bond length is 1.2A° then %of ionic character is
A) 10
B) 20
C) 25
D) 75​

Answer 1

solution :

Given :

Diatomic molecule is 4.32D

Bond length is 1.2A°

we know $1D=10^{-18}eus.cm$

The dipole moment in esu.cm units is $1.2*10^{-18}$

The product of the dipole moment and the interatomic distance is the dipole moment.

it would be $x*$$100*$$10^{-10} =1.2*$$10^{-18}$

$x=$ $1.2$×$10^{-10} eus$

But the electronic charge e= $4.8$×$10^{-10} esu$

Each atom has a partial electrical charge= $\frac{1.2*10^{-10} }{4.8*10^{-10} }*100$

$x=$25%of e

D 25% of e  is correct option .