Question

if the distance btw the points 3,1 and 0,a is 5 units . find the value of a​

Answer 1

Write the point of view of the polynomial x2-4 the point of view of the polynomial x2-4 the point of view of the polynomial x2-4 the point of view of the polynomial x2-4 the point of view of

Step-by-step explanation:

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Answer 2

Answer:

Given, distance between the (3,1) and (0,a) is 5 units.

Step-by-step explanation:

Distance Formula : $\sqrt{(x2-x1)^2+(y2-y1)^2$

(3 , 1)    (0  ,  a)

x1,y1    x2,y2

By substituting the values

$\sqrt{(0-3)^2+(a-1)^2}=5\\\\\sqrt{(-3)^2+(a-1)^2}=5\\\\Squaring On Both Sides\\\\9+(a-1)^2= 25\\\\\\(a-1)^2=25-9\\\\(a-1)^2 = 16\\\\a-1=\sqrt{16}\\\\a-1=4\\\\a=4+1\\ \\a=5$

Therefore a=5

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