The dipole moment of brf is 1.29 d, and its bond length is 178 pm. what is the percent ionic character of the br-f bond?
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Given molecule is BrF
We know, BrF ⇔ Br⁺ + F⁻
Means, if we assume BrF is a system of dipole then, magnitude of charge on each is 1e and it is sperated 178 pm .
we also know, dipole moment = charge × separation between charges
= 1.6 × 10⁻¹⁹ × 178 × 10⁻¹² Cm [ ∵ 1 pm = 10⁻¹² m ]
= 1.6 × 178 × 10⁻³¹Cm
= 1.6 × 178 × 10⁻³¹/3.336 × 10⁻³⁰ D [ 1 D = 3.336 × 10⁻³⁰ Cm]
= 1.6 × 17.8/3.336 D
= 8.537D
Now, % ionic character = given dipole moment/theoretical dipole moment × 100
= 1.29D/8.537 D × 100
= 15.11 %
We know, BrF ⇔ Br⁺ + F⁻
Means, if we assume BrF is a system of dipole then, magnitude of charge on each is 1e and it is sperated 178 pm .
we also know, dipole moment = charge × separation between charges
= 1.6 × 10⁻¹⁹ × 178 × 10⁻¹² Cm [ ∵ 1 pm = 10⁻¹² m ]
= 1.6 × 178 × 10⁻³¹Cm
= 1.6 × 178 × 10⁻³¹/3.336 × 10⁻³⁰ D [ 1 D = 3.336 × 10⁻³⁰ Cm]
= 1.6 × 17.8/3.336 D
= 8.537D
Now, % ionic character = given dipole moment/theoretical dipole moment × 100
= 1.29D/8.537 D × 100
= 15.11 %
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