Question

the dipole moment of HBr is 2.60×1030 Cm the interatomic distanve is 141pm what is the percentage ionic chatacter of HBr

Answer 1

dipole moment =charge x distance between them

=1.6 x 10^-19 x 141 x 10^-12 Cm

=225.6 x 10^-31 Cm

=22.56 x 10^-30 Cm

now,

% of ionic characters

=dipole moment by experimental x 100/dipole moment by theoretical

=(2.6 x 10^-30/22.56 x 10^-30 ) x 100

=260/22.56 %

=11.52 %

Read more on Brainly.in - https://brainly.in/question/1105804#readmore