Question

The directional derivative of the field u x( ,y z, ) x y3 z 2 = in the direction of the vector ( ) i j + 2k t t t at point (2 1 , , - 4) is

Answer 1

Answer:

Step-by-step explanation:

The directional derivative in the z-direction is just ∂f/∂z (or in the opposite direction, which would just be the negative of that). So you just need to compute that, evaluate it at the desired point, and find the conditions on the constants which ensure it is less than 64.

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