the discriminant of 2xsq-3x-5 =0is
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SOLUTION:-
Given:
2x² -3x -5 =0
The roots of the quadratic equation;
Ax² + Bx +C= 0 as compared to:
⚫A=2
⚫B=-3
⚫C=-5
Therefore,
Discriminate, (D)= b² -4ac =0
So,
=) (-3)² - 4(2)(-5) =0
=) 9 - 4(-10) =0
=) 9 - (-40)=0
=) 9 + 40 =0
=) 9 = -40
=) -40/9
Hope it helps ☺️
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