Question

the discriminant of 4x^2–20x+25 is
$({b}^{2} - 4ac)$
​

Answer 1

Answer:

hope it helpss

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

wait for the soln plss

4x²-20x +25

Comparing with,

ax²+bx+c=0

a=4 ,b= -20 c= 25

b²-4ac

$(- 20) ^{2} - 4 \times 4 \times 25$

$= 400 - 400 \\ = 0 \\ therefore \: as \: \\ b {}^{2} - 4ac \: = 0 \\ \\ the \: roots \: are \: real \: and \: equal$