Question

The volume of a right circular cone is 9856cm^(3) .If the diameter of the base is 28cm Find (i) height of the cone (ii) slant height of the cone (iii) curved surface area of the cone

Answer 1

Given:

• r=d/2=>28/2=>14cm

Let height be 'h'

(i) Volume of cone =1/3 pie r²h

=> 9856=1/3×22/7×14×14×h

=>h=48cm

$(ii)slant \: height = \sqrt{r {}^{2} } + \sqrt{h}^{2}$

$\sqrt{14 {}^{2} } + \sqrt{48 {}^{2} }$

$\sqrt{196 + {2430} }$

$slant \: height = 50cm$

(iii) Curved surface area of cone =pie×r×l

=22/7×14×50

=22004cm²

Answer 2

Given:

• R = 14cm

Let height be 'h'

(1) Volume of cone = 1/3πr²h

9856 = 1/3 × 22/7 × 14 × 14 × h

h = 48cm

(2) Slant height = √r² + √h²

√14² + √48²

√196 +2430

slant height = 50cm

(3) curved surface area of cone = πrl

22/7 × 14 × 50

22004cm²

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