Question

The discriminant of the quadractic equation (x-3) (x-4) =0
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Answer 1

Step-by-step explanation:

(x-3)(x-4)

x^2+4x-3x+12

x^2+x+12

Answer 2

Step-by-step explanation:

discriminant = Δ = b²- 4ac

so now

(x-3)(x-4)

x²-7x+12=0

here a=1 , b= (-7) , c= (12)

Δ=(-7)²- 4 (1) (12)

Δ = 49-48=1

discriminant=1