Question

The discriminant of the quadratic equation 3x^2-4x-2=0 is equal to:
(A). 40 (B). 20
(C). 24 (D). 48​

Answer 1

Answer:

3x² - 4x - 2 = 0

here

a = 3

b = - 4

and c = - 2

As we all know the

Discriminant (D) = b² - 4 ac. ......... (i)

Now put the value of variable in equation (i) , we get

D = (- 4 )² - 4 (3) (-2)

D = 16 - (-24)

D = 16 + 24

D = 40

HENCE THE DISCRIMINANT IS 4O

Step-by-step explanation:

I HOPE IT WILL HELP YOU

THANKYOU

Answer 2

Answer:

The correct answer of this question is $40$

Step-by-step explanation:

Given - The discriminant of the quadratic equation 3x^2-4x-2=0 is equal.

To Find - Write the discriminant of the quadratic equation 3x^2-4x-2=0 is equal to-

In the quadratic equation x2 + 4x + 4 = 0, any equation having one term in which the unknown is squared and no term in which it is raised to a higher power solve for x.

According to the question  -

Standard form of a quadratic equation is $ax^{2} +bx +c = 0$

Now, comparing the equation with $3x^{2} - 4x - 2 = 0$ with standard form, we get,

$a = 3, b = -4, c = -2$

Therefore, Discriminat (D) = $b^{2} - 4ac$

D = $(-4^{2}) - 4(3)(-2)$

$16 + 24 = 40$

Discrimiant of the equation is $3x^{2} - 4x - 2 = 0$ is $40$

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