The discriminant of the quadratic equation x^2 - 4x + 4 = 0
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Answered by
10
Answer:
Discriminant b² - 4ac
(4)² - 4 ( 1 ) ( 4 )
16 - 16
= 0
Hence roots are real and equal
- b/2a , -b/2a
-16/2 = -8/1
Hence roots are -8/1 , -8/1
or -8 and -8
Answered by
2
Answer:
Step-by-step explanation:
x² - 4x + 4 = 0
D = b² - 4ac
Here :
b = -4 , c = 4 , a = 1
D = (-4)² - 4 (1)(4)
D = 16 - 16
D = 0
SO THE DICRIMINANT OF X² - 4X + 4 IS ZERO
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