Physics, asked by Sourabhsamaniya, 1 year ago

The displacement(in metres) of a particle moving along x-axis is given by x=18t+5t^2.Calculate: i)instantaneous velocity at t=2s ii)instantaneous acceleration.

Answers

Answered by priyankakundu18
2
1)v= dx/dt= 18+10t= 18 + 10*2= 18 + 20 = 38m/s
2) a= dv/dt = 18
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