Question

The displacement is given as x= 2t^2 +t + 5 ,the acceleration at t=5 Sec will be

Answer 1

at any value of t, acceleration is 4

Answer 2

given displacement x = 2t^2 +t+5
velocity(v) = dx/dt
v= d/dt(2t^2 +t+5)
v= 2(2t)+1
v=4t+1
acceleration (a) = dv/dt
a= d/dt(4t+1)
a=4
acceleration (a) =4 is constant at every instance of time
so acceleration is 4km/hr even at t=5sec