the displacement is given by s= 6t3+4t2-2t+5m. find avg. acc. in 3rd sec.
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Hii....
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Here is ur answer.
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we have displacement (s) = 6t^3+4t^2-2t+5 m.
and Time = 3 sec.
Now,
=> we differentiate two time the dispalcemet over time.
=> d 6t^3+4t^2-2t+5 / dt^2
=> d 18t^2+8t-2 / dt
=> d 36t+8 / dt
=> now we put the value of time.
=> 36×3+8 => 116 m/s.
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☺☺☺
-------------------------
Here is ur answer.
-------------------------
we have displacement (s) = 6t^3+4t^2-2t+5 m.
and Time = 3 sec.
Now,
=> we differentiate two time the dispalcemet over time.
=> d 6t^3+4t^2-2t+5 / dt^2
=> d 18t^2+8t-2 / dt
=> d 36t+8 / dt
=> now we put the value of time.
=> 36×3+8 => 116 m/s.
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☺☺☺
Reyansh05:
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