Physics, asked by lucky5692, 1 year ago

the displacement is given by s= 6t3+4t2-2t+5m. find avg. acc. in 3rd sec.

Answers

Answered by Reyansh05
37
Hii....
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Here is ur answer.
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we have displacement (s) = 6t^3+4t^2-2t+5 m.

and Time = 3 sec.

Now,
=> we differentiate two time the dispalcemet over time.

=> d 6t^3+4t^2-2t+5 / dt^2

=> d 18t^2+8t-2 / dt

=> d 36t+8 / dt

=> now we put the value of time.

=> 36×3+8 => 116 m/s.

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