the displacement is given by x=2t^2+t+5(m).The acceleration at t=2seconds is
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Given
displacement = x= 2t^2 + t + 5
then acceleration = a = dx''/dt
= d/dt(dx/dt) dx/dt = d/dt(2t^2+t+5)
= d/dt( 4t+1) = 4t+1
= 4
therefore the acceleration at t=2s is 4m/s^2
displacement = x= 2t^2 + t + 5
then acceleration = a = dx''/dt
= d/dt(dx/dt) dx/dt = d/dt(2t^2+t+5)
= d/dt( 4t+1) = 4t+1
= 4
therefore the acceleration at t=2s is 4m/s^2
angananirosha:
not understood
ohh... well acceleration is double derivative of the displacemnet
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