The displacement of a particel along x axis is given by x=3+8t+7t^2. Obtain its velocity and accereration at t=2sec
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x = 7t^2 + 8t + 3
For velocity,
differentiating x with respect to time t,
dx / dt = 14t + 8
So, velocity = 14(2)+8 = 36
For acceleration, differentiating x twice w.r.t time,
d2x / dt^2 = 14
Here, acceleration is constant so it would be 14 even at 2 seconds.
For velocity,
differentiating x with respect to time t,
dx / dt = 14t + 8
So, velocity = 14(2)+8 = 36
For acceleration, differentiating x twice w.r.t time,
d2x / dt^2 = 14
Here, acceleration is constant so it would be 14 even at 2 seconds.
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