Question

The displacement of a particle at any instant is given by x=8t square -3t race to the power cube . calculate the average velocity in thr time interval from t= 0 to t=2s and x is t=o and t =3s measured in meter.​

Answer 1

Answer:

-18m/s

Explanation:

Displacement =8t²-3t³

Use differentiation

Displacement= 2×8t-3×3t²

=16t-9t²

=16-18t

Average Velocity=∆D/∆T

= D2-D1/V2-V1

= [16-18(2)-{16-18(0)}]/2-0

= {-20-16}/2

= -18m/s

Average Velocity =D2-D1/T2-T1

=16-18(3)-16-18(0)/3

= 16-54-16/3

= -18m/s

Answer 2

Explanation:

-80 metre per second