Question

The displacement of a particle executing SHM
given by y =0.25 sin 200tcm. The maximu
speed of the particle is:
(1),200 cms-1 (2) 100 cms
3 50 cms-1 (4) 5.25 cms-1​

Answer 1

Answer:

→ (3) 50 cms-1

Explanation:

y =0.25 sin 200t   cm.

y =0.25 sin 200t

v = dy/dt = 50cos200t

The maximu m speed of the particle is: vmax = 50 cm/s

→ (3) 50 cms-1