Question

The displacement of a particle from its mean position (in meter) is given by
Y=0.2 sin (10 t +1.5) cos(10tt +1.5). The motion of the particle is

a)periodic but not SHM
b)Non periodic
c)SHM with period 0.1 sac
d)SHM with period 0.2​

Answer 1

Answer:

0.1seconds

Explanation:

y=0.2sin(10πt++1.5π) cos(10πt++1.5π)  

 =0.1sin2(10πt+1.5π)

 =0.1sin(20πt++3.0π)     [∵sin2A=2sinAcosA]

∴ Time period

=>T=2πω

     =2π20π

     =110

     =0.1sec

hope this helps you Manswi :)