Question

the displacement of a particle in 1d is given by x=t^3-6t^2+3t+4(in metre) . the velocity of the particle when it's Acceleration is zero is____?​

Answer 1

Hello Friend

We need to find acceleration so first differetiating with respect to time gives velocity

v= ds/dt= 6t+14t+5

Further differetiating it gives accleration

a=dv/dt=3+7=10 m/s^2

Dear friend I think your question is like this

s=3t^3+7t^2+5t+8

If it is like this then inform me i wil wrute it again.

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Answer 2

This is the correct answer. It is also a question from previous years entrance papers.