Question

the displacement of a particle is given by x =(t-2)^2 wher x is in metres and t in seconds .the distance covered by the particle in first 4 seconds is

Answer 1

X = (t - 2)2 = t2–4t + 4v = 2t - 4Distance covered = integ(|v|dt) = |t2–4t| = 4t - t2 for t = 0 to 2 = t2 - 4t for t = 2 to 4 = 8 units

this is your ANSWER...

Answer 2

Explanation:

ANSWER

X =(t-2)^2 = t^2–4t + 4

v = 2t - 4

Distance covered = integ(|v|dt)

= |t^2–4t|

= 4t - t^2 for t = 0 to 2

= t^2 - 4t for t = 2 to 4

= 8 units