Question

the displacement of a particle moving in x-axis is given x =18t + 15t^2.find the position at t = 2sec
answer me fast please​

Answer 1

Answer:

Hope it helps u

Explanation:

x=5t

2

+18t

(1)v=

dt

dx

=10t+18

att=2s,v=10×2+18=38m/s

(2)Average,velocity=

time

displacement

att=2,x=5(2)

2

+18×2=56m

t=3,x=5(3)

2

+18×3=99m

Averagevelocity=

3−2

99−56

=43 m/s