Question

The displacement of particle in S.H.M. is x = 2sin(100t + π) . What is its velocity​

Answer 1

the answer of the following questions is 30 m/s

Answer 2

For the displacement of particle in S.H.M. is x = 2sin(100t + π). Its' velocity​ is 0

Explanation:

The velocity of the mass on a spring, oscillating in SHM, can be found by taking the derivative of the position equation: $v ( t ) = d x d t = d d t ( A cos ( ω t + ϕ ) ) = − A ω sin ( ω t + ω ) = − v max sin ( ω t + ϕ )$ . ... The maximum acceleration is a max = $A ω 2 a max = A ω 2$

Position function, $X= 2sin(100t + \pi ) .... 1$

Velocity function,$v= dX/dt = 2πcos(\pi t+\pi ) ... 2$

hence the value of t and v is not mentioned

we take it as $0 t=0,v=0$

when we substitute in 1 and 2

The value of velocity is 0