Physics, asked by StudiousStudent255, 1 year ago

The displacement s of a particle is given by the equation s=t^3-6t^2+9t; where t is measured in seconds and s in meters. what is the velocity(v) after 1 sec. ( given v= ds/dt)

Answers

Answered by PunitB
1
s = t^3-6t^2+9t
v = ds/dt = 3t^2-12t+9 (put t=1)

v = 3-12+9 = 0
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