The displacement s of an object is given as a function of time t s=5t^2+9t. Calculate the instaneous velocity of object at t=0
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Answered by
40
S = 5t^2 + 9t
Differentiate with dt
dS/dt = (5t^2 + 9t)/dt
v = 10t + 9
At t = 0
v = 9
Velocity at t = 0 is 9
Differentiate with dt
dS/dt = (5t^2 + 9t)/dt
v = 10t + 9
At t = 0
v = 9
Velocity at t = 0 is 9
Answered by
12
s=5t^2+9t
for instaneous velocity ,
we have to differentiate displacement with respect to time,
ds/dt=10t+9
now at time =0
velocity=9 meter per second
for instaneous velocity ,
we have to differentiate displacement with respect to time,
ds/dt=10t+9
now at time =0
velocity=9 meter per second
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