Question

The displacement s of particle moving along a straight line is given by, s = 2t3+5t2+6t, where s is in metres and t is in seconds. The initial velocity of the particle is​

Answer 1

Answer: 17m/s

Step-by-step explanation:

Given,

$s=2t^{3}+5t^{2} +6t$

We know that,

$\frac{dv}{dt}=6t^{2}+5t+6$

Initial velocity means when t=0. Putting t=0 in the above equation we get,

$6+5+6\\17 m/s$

Answer 2

hope this will help you. ........