Question

the displacement x of a particle at time t moving along a straight line path is given by x²= at²+ 2bt + c ,where a,b and c are constants . the acceleration of the particle varies as

Answer 1

Hi_________
displacement is x
x^2=at^2+2bt+c
we know that acceleration
a=d^2/dt^2x
i.e.
double differentiat
then
take differential both side with respect to time
we get
2xdx/dt=2at+2b
again differentiate
see in image
hope it help

Answer 2

Answer:

X^-3

Explanation:

Just look at the picture.