The displacement x of a particle is dependent on time t according to the relation : x=3-5t+2t² If t is measured in seconds and x in metres, find its (i) velocity at t = 2s and (ii) acceleration at t = 4s.
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Answer:
velocity=3m/s , acceleration = 4m/s^2
Explanation:
x=3-5t+2t^2
x=2t^2-5t+3
by using differentiation
v=dx/dt= nx^(n-1)
v=2*2t^(2-1)-1*5t^(1-1)+0*3t^(0-1)
v=4t-5
t=2s
v = 4*2 -5
v=8-5
v=3m/s
a=d^2x/dt^2
a=d^2(4t-5)/dt^2
a = 1*4t^(1-1)-0*5t^(0-1
a= 4 m/s^2
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