the displacement x of a particle moving along a straight line is relayed to time by the relation t =x^1/2 + 3. the displacement of the particle when its velocity is zero is given by
Answers
Answered by
16
HI THERE ..
HERE IS UR ANSWER ....
t = x^1/2 + 3
√ x = t - 3
sq both sides
x = ( t - 3 )^2
x = ______(1)
we know
differentiation of distance w.r.t time ,give velocity
so
d (x) / dt = 2 t - 6
v = 2 t - 6
v = 0 ,given
t = 3 second
from eq 1
x = t^2 - 6t + 9
x = 3 × 3 - 6 × 3 + 9
x = 9 - 18 + 9
x = 0
SO DISPLACEMENT WILL BE ZERO
HOPE HELPED
#@®¥@n#
:-)
HERE IS UR ANSWER ....
t = x^1/2 + 3
√ x = t - 3
sq both sides
x = ( t - 3 )^2
x = ______(1)
we know
differentiation of distance w.r.t time ,give velocity
so
d (x) / dt = 2 t - 6
v = 2 t - 6
v = 0 ,given
t = 3 second
from eq 1
x = t^2 - 6t + 9
x = 3 × 3 - 6 × 3 + 9
x = 9 - 18 + 9
x = 0
SO DISPLACEMENT WILL BE ZERO
HOPE HELPED
#@®¥@n#
:-)
Similar questions