Question

The displacement x of a particle moving in one dimension under the action of a constant force is
related to the time t by the equation t = x + 3, where x is in meters and t is in seconds. The
work done by the force in the first 6 seconds is :
(A) 9 J
(B) 6 J
(C) OJ (D) 3 J​

Answer 1

Answer:

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Answer 2

Solution:

★ Given:

➜ The displacement x of a particle moving in one dimension under the action of a constant force is

related to the time t by the equation t = x + 3, where x is in meters and t is in seconds.

★ Find:

➜ Find the work done by the force in the first 6 seconds.

★ Step-by-step:

➜ t = x + 3

➜ x = t - 3

★ Diff. w.r. to t:

➜ dx/dt = d/dt (d - 3)

➜ 1 - 0

➜ +1

★ Diff. w.r to t:

➜ d²x/dt² = d/dt (1)

➜ 0

Hence, Acceleration = 0.

➜ F = m, -a

➜ m × (0)

➜ R = 0

➜ ω = RS

➜ 0 × S

➜ ω = 0

Therefore, the work done by the force in the first 6 seconds is zero.

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