Question

The displacement x of a particle moving in one dimension is related to time t by the relation x = √(2t^2 - 3t), where x is in metres and t is in seconds. Fine the displacement of the particle when velocity is 0

Answer 1

Answer:

answer =0

Explanation:

It is given that

t=

x

+3

⇒x=(t−3)

2

=t

2

+9−6t

Now,

dt

dx

=v=2t−6=0

⇒t=3seconds

Now put t=3seconds

⇒x=0meters