Physics, asked by sdkjack8082, 1 year ago

The displacemwnt in m of a particle is given by x =18+5t²

Answers

Answered by khushboo2632004
0

using diffrentiation method

x = 18t + 5t^2

dx / dt = 18 + 10t

v = 18 + 10t 

t = 2 sec

v = 18 + 10 * 2 

= 18 + 20 

= 38 m / sec

t = 3 sec

v = 18 + 10 * 3

= 18 + 20

= 48 m / s

v(av) = 38 + 48/ 2 

= 43 m/swc

dv / dt = 10

a = 10 m/ s


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