Question

the dissociation constant of a weak monobasic acid La is 1×10^-5 the pH of 0.1M of that acid would be​

Answer 1

Answer:

pH = 3

concept -

Ka = 10^-5

C = 10^-1

{H^+} = √Ka × C

{H+} = √10^-6

H+ = 10^-3

pH = 3

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