Question

The dissociation constant of two acids HA₁ and HA₂ are
3.14 × 10⁻⁴ and 1.96 × 10⁻⁵ respectively. The relative strength
of the acids will be approximately
(a) 1 : 4 (b) 4 : 1
(c) 1 : 16 (d) 16 : 1

Answer 1

The  relative strength  of the acids will be approximately 4 : 1

Option (B) is correct.

Explanation:

• The dissociation constants of HA1  and HA2 are 3 x 10^-4 and 1.8 x 10^-5
• The strength of an acid is directly proportional to square root of dissociation constants of acids.
• So relative strength of the given acids are:
• Relative Acidic Strength = (Acidic Strength)  HA2  /(Acidic Strength) HA1
• Relative Acidic Strength =  √ 3 x 10^-4 / √ 1.8 x 10^-5 = 4.08  = 4

Thus the  relative strength  of the acids will be approximately 4 : 1

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A jar contains mixture of two liquids a & b in the ratio 4:1.when 10 litres of the liquid b is poured in to the jar the ratio becomes 2:3.how many litres of liquid a was contained in the jar?

https://brainly.in/question/5125622

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