Question

The dissociation of nitric acid in water balanced equation

Answer 1

Answer:

Nitric acid decomposes into water, nitrogen dioxide, and oxygen, forming a brownish yellow solution. It is a strong acid, completely ionized into hydronium (H3O+) and nitrate (NO3−) ions in aqueous solution, and a powerful oxidizing agent (one that acts as electron acceptor in oxidation-reduction reactions).

HNO3 + H2O ⇌ H3O+ + NO3

Answer 2

The balanced equation of the dissociation of nitric acid in water is $\[HN{O_3} + {H_2}O \to {H_3}{O^ + } + N{O_3}^ - \]$

Explanation:

• Nitric acid is a strong acid.
• It undergoes dissociation when dissolved in water.
• Dissociation means the breaking of an ionic compound into its ions.
• Therefore, when nitric acid is dissolved in water or reacted with water, it dissociates into its corresponding hydrogen ions ($\[{H^ + }\]$) and nitrate ions ($\[N{O_3}^ - \]$).
• The hydrogen ions are present in the solution in the form of $\[{H_3}{O^ + }\]$ ions.
• Therefore, the balanced equation of the dissociation of nitric acid in water is given as below:

        $\[HN{O_3} + {H_2}O \to {H_3}{O^ + } + N{O_3}^ - \]$

• In this reaction, nitric acid is acid while water is base. $\[{H_3}{O^ + }\]$ is conjugate acid and $\[N{O_3}^ - \]$ is conjugate base.

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