Math, asked by rajatsony2911, 1 year ago

the distance between 2 persons is 800m. if they start moving towards each other simultaneously at 10m/s and 15m/s, in how much time do they meet?

Answers

Answered by TooFree
2

Let the 2 persons be Person A and Person B


Person 1 moves at 10m/s

1 sec = 10 m


Person 2 moves at 15 m/s

1 sec = 15 m


Find the total distance covered by both of them in 1 second:

Total distance = 10 + 15 = 25 m


Find the total number of seconds needed for the them to meet:

1 second = 25 m

Total distance = 800 m

Total number of seconds needed = 800 ÷ 25 = 32


Answer: They will need in 32 seconds.



Answered by ashmishah16pd56ff
0
It is a relative velocity sum
relative velocity= total distance/ sum of speeds
So 800/(10+15)=800/25=32s
pls mark it as brainliest answer
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