The distance between 2 stations is 216 km. A bus takes 3 hours to cover this distance. Calculate the average speed of the bus in m/s.
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Answered by
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average velocity(v) = displacement/time
⇒v = 216/3 v = 72 km/hr
⇒v = 72 × 1000 m / 3600 s (1 km = 1000 m and 1 hr = 60 x 60 sec, we can also multiply it with 5/18 as we see 1000 m / 3600 hr = 5 m/18 s)
⇒v = 2 × 1000 m / 100 s
⇒v = 20 m/s
⇒v = 216/3 v = 72 km/hr
⇒v = 72 × 1000 m / 3600 s (1 km = 1000 m and 1 hr = 60 x 60 sec, we can also multiply it with 5/18 as we see 1000 m / 3600 hr = 5 m/18 s)
⇒v = 2 × 1000 m / 100 s
⇒v = 20 m/s
Anonymous:
hope it helps
Answered by
1
Answer:
average velocity(v) = displacement/time
⇒v = 216/3 v = 72 km/hr
⇒v = 72 × 1000 m / 3600 s (1 km = 1000 m and 1 hr = 60 x 60 sec, we can also multiply it with 5/18 as we see 1000 m / 3600 hr = 5 m/18 s)
⇒v = 2 × 1000 m / 100 s
⇒v = 20 m/s
Explanation:
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