the distance between 4x+3y=11 and 8x+6y=15 is?
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4x + 3y = 11 meets the x-axis at x = 11/4
8x + 6y = 15 meets the x-axis at x = 15/8
distance between the two points = 11/4 - 15/8 = 7/8
if the acute angle either line makes with the x-axis is u, then tanu = 4/3 and sinu = 4/5.
distance between the two lines is (7/8)sinu = 7/8 x 4/5 = 7/10.
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